If you would like to solve the system of equations, you can do this using the following steps:

4x^2 + 9y^2 = 72
2x - y = 4 ... 2x - 4 = y
_________
4x^2 + 9y^2 = 72
4x^2 + 9 * (2x - 4)^2 = 72
4x^2 + 9 * (4x^2 - 16x + 16) = 72
4x^2 + 36x^2 - 144x + 144 = 72
40x^2 - 144x + 144 - 72 = 0
40x^2 - 144x + 72 = 0
10x^2 - 36x + 18 = 0
5x^2 - 18x + 9 = 0
(5x - 3) * (x - 3) = 0
1. 5x - 3 = 0 ... 5x = 3 ... x = 3/5
2. x = 3

1. y = 2x - 4 = 2 * 3/5 - 4 = 6/5 - 20/5 = -14/5
2. y = 2x - 4 = 2 * 3 - 4 = 6 - 4 = 2

1. (x, y) = (3/5, -14/5)
2. (x, y) = (3, 2)

The correct result would be (3/5, -14/5) and (3, 2).

5 0

2 years ago

Bailey and Elena compete in a swim race

gogolik [260]

Answer:

yaah then bailey has fun with her

Step-by-step explanation:

5 0

3 years ago

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

$m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\$

$m_{2}=$ -1 ÷ $m_{1}$

= $-1*\frac{2}{5}=\frac{-2}{5}$

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

y - [5] = $\frac{-2}{5}(x - [-3])\\$

$y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\ y =\frac{-2}{5}x-\frac{6}{5}-5\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}$

5 0

3 years ago

Identify the sets of lines to which the given line is a transversal. Line m

Alekssandra [29.7K]

Answer:

Only J and I

Step-by-step explanation:

Transversal Lines are only transversal to sets of parallel lines in which they pass through and P is not parallel to any.

8 0

2 years ago