The two interior angles will be congruent.
Hope this helps :)
x2=36
We move all terms to the left:
x2-(36)=0
We add all the numbers together, and all the variables
x^2-36=0
a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ‾‾√=144‾‾‾‾√=12
x1=−b−Δ√2a=−(0)−122∗1=−122=−6
x2=−b+Δ√2a=−(0)+122∗1=122=6
Definitely not. They are both perfect squares. A prime number is one where its only factors are one and itself.
Retire zero la bour li dan trou fess to pu ggnr bon
The angle is sin inverse 0.3535 which is around 21 degrees
