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guajiro [1.7K]
3 years ago
7

PLEASE HELP ASAP FOR 10 POINTS

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

-a³b²c² - a²b³c² + a²b²c³

Step-by-step explanation:

-a²b²c²(a+b-c)= -a³b²c² - a²b³c² + a²b²c³

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How many times does the digit 7 appear among the terms of the sequence of consecutive integer numbers 7, 8, 9, ...., 777?
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Answer:

234 times

Step-by-step explanation:

<u>Number of times the number 7 appears in a hundred</u>

7 as units digit (07-17-27 ..... 97): 10 times

7 as tens digit (70-71-72..... 79): 10 times

20 times the digit 7 appears in first one hundred (0-100)

Let's calculate how many times 7 would be as units or tens in 7 hundreds

20X7 = 140 times digit 7 appears until number 699

<u>Now, from 700 to 777</u>

7 as hundreds digit (700-701-702 .... 777): 78 times

7 as tens digit (770-771-772 .... 777): 8 times

7 as units digit (707-717-727....777): 8 times

78 + 8 + 8 = 94 times the digit 7 appears in the range 700 - 777. Plus 140 times

140 + 94 = 234 times

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