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Artyom0805 [142]
3 years ago
15

Simplify the variable expression by evaluating its numerical part.

Mathematics
1 answer:
Virty [35]3 years ago
6 0
You can use this one app it’s called Cymath it’s really helpful with these types of problems,
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there is a walking trail at the park. four laps around the trail is a distance of 1 mile. how many laps does it take to walk 3/4
dybincka [34]
1 ÷ 4 1/4 so one lap is a quarter of a mile meaning 3 laps is 3/4 of a mile
4 0
3 years ago
Which of these relations on{0,1,2,3}are partial orderings? Determine the properties of a partial ordering that the others lack.
omeli [17]

Step-by-step explanation:

A = {0,1,2,3}

a): R = {(0,0),(2,2),(3,3)}

R is antisymmetric, because if the (a,b)∈R, than a=b.

R is not reflexive, because (1,1) ∉ R while 1 ∈ A.

R is transitive, because if the (a,b)∈R and (b, c) ∈ R, than a=b=c and (a,c)=(a,a)∈R.

R is not portable ordering because R is not reflexive.

b): R = {(0,0),(1,1),(2,0),(2,2),(2,3),(3,3)}

R is antisymmetric, because if the (a,b)∈R and if the (b, a) ∈ R, than a=b (since (2,0) ∈ R and (0,2) ∉ R; and (2,3) ∈ R and (3,2) ∉ R )

R is reflexive, because (a,a) ∈ R of every element a ∈ A.

R is transitive , because if the (a,b)∈R and if the ( b , c )∈R . then a = b or b = c ( since there are only two element not of the form ( a , a ) and that pair does not satisfy ( a,b ) ∈ R and ( b , a ) ∈ R ), which implies ( a , c ) = ( b , c ) ∈ R or ( a , c ) = ( a , b ) ∈ R.

R is a partial ordering, because R is reflexive, antisymmetric and transitive.

c): R =  {(0,0),(1,1),(1,2),(2,2),(3,1),(3,3)}

R is reflexive, because (a,a)∈R of every element a ∈ A.

R is antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R . then a = b ( since ( 1 , 2 )∈R and ( 2 , 1 ) ∉ R; ( 3 , 1 ) ∈ R and ( 1 , 3 ) ∉ R ).  

R is not transitive , because ( 3 , 1 ) ∈ R and ( 1 , 2 )∈R, while ( 3 , 2 ) ∈ R.

R is not a partial ordering. because R is not transitive .

d): R =  {(0,0),(1,1),(1,2),(1,3),(2,0),(2,2),(2,3), (3,0),(3,3)}

R is the reflexive, because ( a , a )∈R of every elements∈A.

R is the antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R, then a = b ( since ( 1 . 2 )∈R and ( 2 . 1 )∉R; similarly, all other elements not of the form (a,a) ).

R is not transitive, because ( 1 , 2 )∈R and ( 2 , 0 )∈R, while ( 1 . 0 )∉R.

R is not a partial ordering, because R is not transitive,

e):  R = { ( 0 , 0 ) , ( 0, 1 ) , ( 0 , 2 ) , ( 0 , 3 ) , ( 1 , 0 ) , ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 2 , 0 ) , ( 2 , 2 ) , ( 3 , 3 ) }

R is the reflexive , because ( a , a )∈R of every element a∈A .

R is not antisymmetric, because ( 1 , 0 )∈R and ( 0 , 1 )∈R while 0 is not equal to 1.

R is not transitive, because ( 2 , 0 )∈Rand ( 0 , 3 )∈R, while ( 2 , 3 )∉R .

R is not a partial ordering, because R is not the antisymmetric and not the transitive.

3 0
3 years ago
Use the rational root theorem to list all possible rational roots for the equation.
Alik [6]

Answer:

The possible rational roots are

\pm 1, \pm 2,\pm3,\pm6,\pm \frac{1}{3},\pm \frac{2}{3}

Step-by-step explanation:

We have been given the equation 3x^3+9x-6=0 and we have to list all possible rational roots by rational root theorem.

The factors of constant term are 1, 2, 3,6

The factors of leading coefficient are  1,3,

From ration root theorem, the possible roots are the ratio of the factors of the constant term and the factors of the leading coefficient. We include both positive as well as negative, hence we must include plus minus.

\pm\frac{1,2,3,6}{1,3}\\\\ =\pm 1, \pm 2,\pm3,\pm6,\pm \frac{1}{3},\pm \frac{2}{3}


5 0
3 years ago
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Helppp, determine the indicated lengths
Nady [450]

Answer:

phuk u uagsgshwgwgdgwgwyegwgwgwhehehehe

8 0
2 years ago
3*3*3*3*3^2 write as a single power
e-lub [12.9K]

Answer:

3^6

Step-by-step explanation:

<u>Step 1:  Find the single power of these numbers</u>

<u />3 * 3 * 3 * 3 * 3^2

(3 * 3 * 3 * 3) * 3^2

3^4 * 3^2

3^(^4^+^2^)

3^6

Answer:  3^6

3 0
3 years ago
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