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rodikova [14]
3 years ago
13

write the equation of a line with that passes through given point and gas the given slope. Answer in general form​

Mathematics
1 answer:
KiRa [710]3 years ago
8 0

Step-by-step explanation:

c) since m = undefined => the equation is

x = -2

d) the equation is

y-2= -1/7 (x+7)

=> y = -1/7 x -1+2

<=> y = -1/7 x + 1

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How to rewrite 2+2+2+2+2 into a multiplication problem?
inna [77]

Answer:

2 x 5

Step-by-step explanation:

Think of it as "the value 2 is being added together 5 times" being added together so it could be written as 2 times 5.

5 0
3 years ago
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I have to turn that into the simplest form
zimovet [89]

5.006=5\frac{6}{1000} =5\frac{3}{500}...or...\frac{2,503}{500}

Hope this helps!

8 0
3 years ago
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A bank is offering 2.5% simple interest on a savings account. If Jayden deposits $5000,
Ahat [919]

Answer:

$2250

Step-by-step explanation:

First, find how much more Jayden will get each month by doing 2.5% of 5000, or multiplying 0.025 * 5000 = $125 per month.

Then, since Jayden is leaving it there for 18 months, you can do 125 * 18 = 2250.

The interest he will earn is $2250

8 0
2 years ago
In the reaction 2HgO(s) --&gt; 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginnin
djverab [1.8K]

Answer:

0.034 L/min

Step-by-step explanation:

The rate of reaction is the volume change (ΔV) divided by the time(t) and divided by the coefficient of the compound in the reaction. The coefficient of O₂ is 1, so:

R = (0.36 - 0.02)/10

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4 0
3 years ago
A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a
DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}

Then the mean (first moment) is

E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710

and the second moment is

E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3

The second moment is useful in finding the variance, which is given by

V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3

You get the standard deviation by taking the square root of the variance, and so

\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09

8 0
3 years ago
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