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rodikova [14]
2 years ago
13

write the equation of a line with that passes through given point and gas the given slope. Answer in general form​

Mathematics
1 answer:
KiRa [710]2 years ago
8 0

Step-by-step explanation:

c) since m = undefined => the equation is

x = -2

d) the equation is

y-2= -1/7 (x+7)

=> y = -1/7 x -1+2

<=> y = -1/7 x + 1

You might be interested in
A graph has the equation Y=x/8 what is the constant of proportionality
aev [14]

Answer: 1/8x

Step-by-step explanation:

y= 1/8x

below are the x:y relationships

x:y

4:0.5

8:1

12: 1.5

16:2

20:2.5

24:3

28:3.5

32:4

etc.

7 0
3 years ago
Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

5 0
3 years ago
Camille shaded _1 8
san4es73 [151]

Answer:

you are saying it wrong its 1\8 and 3\3

Step-by-step explanation:

5 0
2 years ago
The first number in a pattern is 8. Each following number is found by subtracting 9 from the previous
ser-zykov [4K]

Answer:

8,-1,-9,-18,-27,-36

and so on i would think it would be -27

Step-by-step explanation:

3 0
3 years ago
What is the product of 4/5 × 2/5​
gtnhenbr [62]

Answer:

8/25

Step-by-step explanation:

4/5 *2/5

Multiply the numerators

4*2 = 8

Multiply the denominators

5*5 = 25

8/25

7 0
3 years ago
Read 2 more answers
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