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4 years ago

In quadrilateral PQRS, the coordinates are P(o, o), Q(a+c, o), R(2a+c,

1 answer:

alexandr1967 [171]4 years ago

7 0

Given:
Quadrilateral PQRS
P(o, o), Q(a+c, o), R(2a+c, b), S(a, b)
Find:
whether the diagonals are perpendicular using coordinate geometry
Solution:
If the diagonals are perpendicular, their slopes multiply to give -1.
The slope of PR is
(b-o)/(2a+c-o)
The slope of QS is
(b-o)/(a-(a+c)) = (b-o)/(-c)
The product of these slopes is
(b-o)·(b-o)/((2a+c-o)(-c))
This value will not be -1 except for very specific values of a, b, c, and o.

It cannot be concluded that the diagonals of PQRS are perpendicular based on the given coordinates.

You might be interested in

What is the probability of flipping a coin 10 times and getting tails 7 times ? Round your answer to the nearest tenth of a perc

KatRina [158]

Answer:

Option C: 11.7%

Step-by-step explanation:

The number of elements in sample space when a coin is flipped 10 times will be:

$n(S) = 2^{10} \\= 1024$

Let A be the event that the tails appear 7 times:

Then,

$C_{(n,k)}=\frac{n!}{(k!)(n-k)!} \\where\\n=population\\k=picks\\In our case, k =7\\and\\n=10\\C_{(10,7)}= \frac{10!}{(7!)(10-3)!}\\= 120\\So, \\P(A) = \frac{n(A)}{n(S)} \\P(A) = \frac{120}{1024} \\= 0.1171\\$

Converting into percentage:

$P(A) = 0.1171*100=11.7%$

So, option C is correct ..

6 0

3 years ago

What is an equation of the line that passes through the points (-8, 2) and (-4, -3)?

denpristay [2]

Answer:

y = (-6/13)x + (4/13).,

Step-by-step explanation:

the equation of the line is:

y = mx + b, where "m" is the slope and "b" gives the y-intercept

m = (y2 - y1)/(x2 - x1)

m = (-2 - 4)/(5 - (-8))

m = -6/13

y = (-6/13)x + b

the line passes through the point (-8,4) means that for x = -8, y = 4

4 = (-6/13)(-8) + b

b = 4 - (-6/13)(-8)

b = 4/13

the equation of the line that passes through the points (-8,4) and (5,-2) is:

y = (-6/13)x + (4/13).

5 0

3 years ago

PLEASE HELP! WILL MARK BRAINLIEST

Veseljchak [2.6K]

The value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.

<h3>How to determine the dimensions?</h3>

The given parameters are:

Base = 5(x+3)

Height = 2(x+9)

Perimeter = 108

The perimeter of a rectangle is

P = 2 *(Base + Height)

So, we have:

2 *(5(x + 3) + 2(x + 9)) = 108

Divide both sides by 2

5(x + 3) + 2(x + 9) = 54

Open the brackets

5x + 15 + 2x + 18 = 54

Evaluate the like terms

7x = 21

Divide by 7

x = 3

Substitute x = 3 in Base = 5(x+3) and Height = 2(x+9)

Base = 5(3+3) = 30

Height = 2(3+9) = 24

Hence, the value of x is 3, while the length of the rectangle is 30 units and the width is 24 units.

Read more about perimeter at:

brainly.com/question/24571594

#SPJ1

5 0

2 years ago

Approximate <img src="https://tex.z-dn.net/?f=-8%20%2B%5Csqrt%7B20%7D" id="TexFormula1" title="-8 +\sqrt{20}" alt="-8 +\sqrt{20}

alisha [4.7K]

The value of the radical expression -8 + √20 when expanded and solved is -3.6, based on the given parameters

<h3>What are equivalent expressions?</h3>

Equivalent expressions are different expressions that have equal values when evaluated and compared

<h3>How to approximate the radical expression?</h3>

The expression is given as:

-8 + √20

The above expression is a radical expression

So, we start by doing the following

Express 20 as 5 * 4

-8 + √20 = -8 + √(5 * 4)

Split the radical expression √(5 * 4)

-8 + √20 = -8 + √5 * √4

Evaluate the square root of 4 i.e. √4 = 2

-8 + √20 = -8 + √5 * 2

This gives

-8 + √20 = -8 + 2√5

Evaluate the square root of 5

-8 + √20 = -8 + 2 * 2.2

Evaluate the product of 2 and 2.2

-8 + √20 = -8 + 4.4

Evaluate the difference

-8 + √20 = -3.6

Based on the given parameters, the value of the radical expression -8 + √20 when expanded and solved is -3.6

So, the complete equation is:

-8 + √20 = -3.6