E(1,-4) F(1,-6) G(-3,-5) H(-3,-3)
Answer:
.
Step-by-step explanation:
Over this interval, the change in the value of this function is:
.
The corresponding change in the value of 
:
.
The average rate of change of function 
over this interval is equal to the change in the function value divided by the corresponding change in :
.
Thus, the average rate of change of 
over the interval ![[-5,\, 2]](https://tex.z-dn.net/?f=%5B-5%2C%5C%2C%202%5D)
would be .
Answer:
17) MC(x) = 35 − 12/x²
18) R(x) = -0.05x² + 80x
Step-by-step explanation:
17) The marginal average cost function (MC) is the derivative of the average cost function (AC).
AC(x) = C(x) / x
MC(x) = d/dx AC(x)
First, find the average cost function:
AC(x) = C(x) / x
AC(x) = (5x + 3)(7x + 4) / x
AC(x) = (35x² + 41x + 12) / x
AC(x) = 35x + 41 + 12/x
Now find the marginal average cost function:
MC(x) = d/dx AC(x)
MC(x) = 35 − 12/x²
18) x is the demand, and p(x) is the price at that demand. Assuming the equation is linear, let's use the points to find the slope:
m = (40 − 50) / (800 − 600)
m = -0.05
Use point-slope form to find the equation of the line:
p(x) − 50 = -0.05 (x − 600)
p(x) − 50 = -0.05x + 30
p(x) = -0.05x + 80
The revenue is the product of price and demand:
R(x) = x p(x)
R(x) = x (-0.05x + 80)
R(x) = -0.05x² + 80x
This problem can be solved using dimensional analysis.
