Question

In an 18-meter race between a tortoise and a hare, the tortoise leaves 23 minutes before the hare. The hare, by running at an average speed of 0.5 meter per hour fast than the tortoise, crosses the finish line 1 minute before the tortoise. What are the average speeds of the tortoise and the hare?

Answer 1

We know that:
time=distance/speed
if the tortoise speed is x m/min, then since 0.5 m/hr=1/120 m/min
18/x=23+18/(x+1/120)
solving for x we get:
x=0.08 m/min
speed of hare is:
(0.08+1/120)=0.088 m/min