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3 years ago

What are the apparent coordinates of the midpoint of diagonal AC?

Mathematics

1 answer:

photoshop1234 [79]3 years ago

6 0

Point A is (-2,2) and point C is(3,0) so the midpoint is

$\left( \dfrac{-2 + 3}{2}, \dfrac{2 + 0}{2} \right) = \left( \dfrac 1 2, 1 \right)$

Choice A

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3 years ago

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2 years ago

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The graph of g(x) is a transformation of the graph of f(x)=3x. Enter the equation for g(x) in the box. G(x) =.

dalvyx [7]

Function transformation involves changing the form of a function

The function g(x) is $\mathbf{g(x) = 8(2)^x}$

The function is given as:

$\mathbf{f(x) = 3^x}$

g(x) is an exponential function that passes through points (-2,2) and (-1,4).

An exponential function is represented as:

$\mathbf{y = ab^x}$

At point (-2,2), we have:

$\mathbf{2 = ab^{-2}}$

At point (-1,4), we have:

$\mathbf{4 = ab^{-1}}$

Divide both equations

$\mathbf{\frac 42=\frac{ab^{-1}}{ab^{-2}}}$

Simplify

$\mathbf{2=\frac{b^{-1}}{b^{-2}}}$

Apply law of indices

$\mathbf{2=b^{-1+2}}$

$\mathbf{2=b}$

Rewrite as:

$\mathbf{b =2}$

Substitute 2 for b in $\mathbf{2 = ab^{-2}}$

$\mathbf{2 =a(2^{-2})}$

This gives

$\mathbf{2 =a(\frac 14)}$

Multiply both sides by 4

$\mathbf{a = 8}$

Substitute 8 for (a) and 2 for (b) in $\mathbf{y = ab^x}$

$\mathbf{y = 8(2)^x}$

Express as a function

$\mathbf{g(x) = 8(2)^x}$

Hence, the function g(x) is $\mathbf{g(x) = 8(2)^x}$

Read more about exponential functions at:

brainly.com/question/11487261

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2 years ago

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