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3 years ago

Which statement best describes the zeros of the function h(x) = (x-4)2(x - 7x + 10)?

Mathematics

1 answer:

mel-nik [20]3 years ago

4 0

Answer:

where are the options

Step-by-step explanation:

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What is the value of y in the equation 2(3y - 6) = 0?

Fittoniya [83]

Answer:

The answer is y=2

Step-by-step explanation:

6 0

3 years ago

Hi! I need to know if I would be correct on this...

V125BC [204]

I think you're right:

6 0

3 years ago

-x+ 2y = 10<br> -3x+By = 11

adoni [48]

Answer:

change the equation into one variable.

2 y equals 10 + x

y equals 5 + x by 2

now put that into the second equation

-3x + b parentheses 5 + x / 2 equals 11

-3x+b(5+ x/2)

-3x + b5 + bx/2 = 11

8 0

3 years ago

Read 2 more answers

Bad at math... help please ):

zavuch27 [327]

Smallest side XYZ/ Smallest side ABC = Longest side XYZ/ Longest side ABC
Let longest side XYZ be x
280/112 = x/144
x = (280/112)×144
x = 360
Option D will be your answer

Hope it helped!

3 0

3 years ago

Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand

kvasek [131]

Answer:

(a) $\frac{5}{7},\frac{1}{6}$ (b) $\frac{1}{7},\frac{1}{6}$ (c) $\frac{5}{7},\frac{2}{3},\frac{3}{5}$

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with $5$ blue marbles, $1$ white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag $=7$

(a)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(b)

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{7}$

As marble is not returned to bag,

Probability of drawing white marble $=\frac{\text{total white marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(c)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing second blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{4}{6}=\frac{2}{3}$

As marble is not returned to the bag

Probability of drawing third blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{3}{5}$

8 0

3 years ago