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8_murik_8 [283]
3 years ago
11

What is 4.7 times 10 to the negative third power (show your work)

Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Since we are working with an equation written in scientific notation and we are dealing with a negative exponent, we are going to divide 4.7 by 10 three times.

4.7 / 10 = 0.47

0.47 / 10 = 0.047

0.047 / 10 = 0.0047

Best of Luck!

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Find the fifth term in the geometric sequence for a1=2 and r=3
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D=4Step-by-step explanation:

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3 years ago
A piece of wood is divided into two pieces in the ratio of 2:5. One piece is 10 cm long so how long is the other piece?
klio [65]

Answer:

The length of the pother piece of the wood is 25 cm.

Step-by-step explanation:

Let the length of a piece of wood is x such that the ratio of two pieces is 2:5. Two pieces are 2x and 5 x

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We have considered that the length of other piece is 5x. It means 5×5 = 25 cm.

Hence, the length of the pother piece of the wood is 25 cm

8 0
3 years ago
If f(x)= -5 -7x, find f(-2)
swat32

Answer:

Given f(-2)

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4 0
3 years ago
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Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
In the polynomial 4x3 + 5x2 − 12, what is the coefficient of the x2 term?
Elza [17]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
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