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Sonbull [250]
3 years ago
12

I'M GIVING 100 POINTS FOR THIS What is the ratio of a surface area to volume of a sphere with the following measurements? Surfac

e Area = 300m2 Volume = 500m3 A. 500m -1 B. 0.6m -1 C. 300m-1 D. 1.7m-1
Mathematics
2 answers:
marissa [1.9K]3 years ago
8 0

Answer:

B

Step-by-step explanation:

SA/V = 300m^2/500m^3 -------- m^2 cancel out and so d othe 100

we get 3/(5m)

Sooo, I guess that's equal to 3/5 1/m and 1/m is m^-1 so we have (B)

Setler79 [48]3 years ago
4 0

Answer: 500m^-1

Step-by-step explanation:

APEX

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2 years ago
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3 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

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(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

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Answer:

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or

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Answer:

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