I NEED HELP!!<br><br> What is the interquartile range (IQR) of the data?

Plz plz help me with this

Grace [21]

A) set them equal to 180° so it should be 180=5x+10 and x=34 plug it in and VRX=56° and WRV=124°

7 0

3 years ago

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

7 0

4 years ago

If the area of Bianca’s rectangular backyard patio is represented by the expression x2−18x + 81, and the length of the patio is

frosja888 [35]

Answer:

a square backyard with width (x - 9)

Step-by-step explanation:

x²−18x + 81 = x² - (2 x 9) x + 9² = (x - 9)²

width = area / length = (x - 9)² / (x - 9) = x - 9

Length = width

This is a square backyard

4 0

3 years ago

The tables represent two linear functions in a system.

tino4ka555 [31]

first function 2nd function

slope =(y2-y1)/(x2-x1) slope =(y2-y1)/(x2-x1)

=(14-2)/(3-0) m = (-3--12/(3-0)

12/3 m=(-3+12)/3

4 m =9/3 =3

y = 4x+2 y = 3x+-12

set these two equations equal

4x+2 = 3x-12

subtract 3x

x+2 = -12

subtract 2 from each side

x = -14

y = 3x-12

y =3*(-14)-12

y = -42-12

y = -54

ChoiceD

3 0

3 years ago

Read 2 more answers

Find the values of x and y if 5 ˣ⁻³ x 3²ʸ⁻⁸ =225

-BARSIC- [3]

Answer:

x = 5, y = 5

Step-by-step explanation:

${5}^{x - 3} \times {3}^{2y - 8} = 225 \\ {5}^{x - 3} \times {3}^{2y - 8} = 25 \times 9 \\ {5}^{x - 3} \times {3}^{2y - 8} = {5}^{2} \times {3}^{2} \\ equating \: like \: power \: terms \: from \: both \:\\ sides \\ {5}^{x - 3} = {5}^{2} \\ x - 3 = 2 (Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ x = 3 + 2 \\ \huge \red{ \boxed{ x = 5}} \\ \\ {3}^{2y - 8} = {3}^{2} \\ 2y - 8 = 2(Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ 2y = 2 + 8 \\ 2y = 10 \\ y = \frac{10}{2} \\ \huge \purple{ \boxed{y = 5}}$

5 0

3 years ago

I NEED HELP!! What is the interquartile range (IQR) of the data?