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2 years ago

There are 52 weeks in a year. Ben has lived in london for two fifths of year. How many weeks has ben lived in london?

2 answers:

6 0

$\text{We're trying to find how many weeks Ben has lived in London}\\\\\text{We know that there are 52 weeks in a year}\\\\\text{We also know that he's been in London for 2/5 of a year, or 40\%}\\\\\text{To find your answer, you could multiply 52 by 0.40}\\\\52*0.40= 20.8\\\\\boxed{\text{Ben has been in London for 20.8 weeks}}$

masha68 [24]2 years ago

5 0

Answer:

$\frac{104}{5}$ weeks or $20\frac{4}{5}$ weeks

Step-by-step explanation:

To do this we can set up a proportion

$\frac{52}{1} *\frac{2}{5}$

This will tell us how many weeks are in 2/5 of a year

Let's evaluate this

$\frac{104}{5}$

We cannot simplifiy this anymore, so we will leave it as an improper fraction, or a mixed number as shown below

$20\frac{4}{5}$ weeks

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2 years ago

16. A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours

Reika [66]

Answer:

a) 23.11% probability of making exactly four sales.

b) 1.38% probability of making no sales.

c) 16.78% probability of making exactly two sales.

d) The mean number of sales in the two-hour period is 3.6.

Step-by-step explanation:

For each phone call, there are only two possible outcomes. Either a sale is made, or it is not. The probability of a sale being made in a call is independent from other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A telemarketer makes six phone calls per hour and is able to make a sale on 30% of these contacts. During the next two hours, find:

Six calls per hour, 2 hours. So

$n = 2*6 = 12$

Sale on 30% of these calls, so $p = 0.3$

a. The probability of making exactly four sales.

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{12,4}.(0.3)^{4}.(0.7)^{8} = 0.2311$

23.11% probability of making exactly four sales.

b. The probability of making no sales.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3)^{0}.(0.7)^{12} = 0.0138$

1.38% probability of making no sales.

c. The probability of making exactly two sales.

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.3)^{2}.(0.7)^{10} = 0.1678$

16.78% probability of making exactly two sales.

d. The mean number of sales in the two-hour period.

The mean of the binomia distribution is

$E(X) = np$

$E(X) = 12*0.3 = 3.6$

The mean number of sales in the two-hour period is 3.6.

4 0

3 years ago

Please I need the correct answer please

Rzqust [24]

(−1

2 )(n^3)+

1

2 n^2+4.6n+(−

1

2)(n^3)+

1

2 n^2+4.5n

−1

2 n^3+

2 n^2+4.6n+

−1

2 n^3+

2 n^2+4.5n

Combine Like Terms:

−1

2 n^3+

1

2 n^2+4.6n+

−1

2 n^3+

1

2 n^2+4.5n

=(−1

2 n^3+

−1

2 n^3)+(

1

2 n^2+

1

2 n^2)+(4.6n+4.5n)

=−n^3+n^2+9.1n

Answer:

=−n^3+n^2+9.1n

Everything underlined means its a fraction/divided hope this helps :D

8 0

3 years ago

3. Bobbi bought 4 rolls of

sveta [45]

Answer:

400 x however long those ribbons are

Step-by-step explanation:

1 meter is 100 centimeters, and there are four rolls. so 4x100 equals 400, and you multiply that by the length that you didn't provide.

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1 year ago

Madison wants to buy a new iPhone. The regular price is $989. Apple is offering a 15% discount and a sales tax of 7% is added af

Rzqust [24]

Answer: $899.50

Step-by-step explanation:

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2 years ago