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AysviL [449]
3 years ago
5

Please help me with this step by step.

Mathematics
1 answer:
Drupady [299]3 years ago
6 0

Answer:

\large\boxed{y=-\dfrac{1}{5}x+\dfrac{3}{5}}

Step-by-step explanation:

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2\\=========================

\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=-\dfrac{1}{5}.\\\\\text{Put the value of a slope and the coordinates of the given point}\ (-2,\ 1)\\\text{to the equation of a line}\ y=mx+b:\\\\1=-\dfrac{1}{5}(-2)+b\\\\1=\dfrac{2}{5}+b\qquad\text{subtract}\ \dfrac{2}{5}\ \text{from both isdes}\\\\1-\dfrac{2}{5}=\dfrac{2}{5}-\dfrac{2}{5}+b\\\\\dfrac{5}{5}-\dfrac{2}{5}=b\to b=\dfrac{3}{5}\\\\\text{Finally:}\\\\y=-\dfrac{1}{5}x+\dfrac{3}{5}

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Step-by-step explanation:

We know that if y varies directly with x, we can express the relationship such as

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Given

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