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Blababa [14]
2 years ago
12

An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How

many of the ants should be alive after 4 months? (Round to the whole ant.)
Mathematics
2 answers:
motikmotik2 years ago
6 0

Answer: 917 ants should be alive after 4 months.

Step-by-step explanation:

As each month goes by in the winter, 6.5% of the population dies off. It means that the population is decaying exponentially. We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the population after t months.

t represents the number of months.

P represents the initial population.

r represents rate of decay.

From the information given,

P = 1200

r = 6.5% = 6.5/100 = 0.065

t = 4 months

Therefore,

A = 1200(1 - 0.065)^4

A = 1200(0.935)^4

A = 917

Nitella [24]2 years ago
5 0

Answer:

There will be 916 ants alive after 4 months.

Step-by-step explanation:

Step 1

Let's change the percentage to a decimal by dividing by a 100.

6.5% / 100 = .065

Step 2

So, for the first month we will multiply the initial amount of ants by .065 and this will give us the number of ants that die.

1200 * .065 = 78

This means that after the first month, 1200 - 78 = 1122 ants will be alive.

Step 3

Now for the second month: 1122 * .065 = 72.93 (rounded to 73)

1122 - 73 = 1049 ants will be alive

Step 4

For the third month 1049 * .065 = 68.185 (rounded to 68)

1049 - 68 = 981 ants will be alive

Step 5

For the fourth month 981 * .065 = 63.765 (rounded to 64)

981 - 64 = 916 ants will be alive

Hope this helps!

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Step-by-step explanation:

3 0
2 years ago
In the figure, one side of the rectangle divides the circle in half.
Setler79 [48]
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6 0
3 years ago
I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th
stellarik [79]

Answer:

The number of once is 9.1  

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18             .........1

100 × H + 1 × O = 900          ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴   H = \frac{882}{99}

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e  O = 18 - 8.9

∴    O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1  and The number of hundreds is 8.9

Answer

4 0
3 years ago
Solve the expression for x: (17 – 5) (x + 6) = 3x – 12
patriot [66]

(17-5)(x+6)-(3x-12)=0

12(x+6)-(3x-12)=0

12x-(3x-12)+72=0

12x-3x+12+72=0

9x+84=0

9x=-84

x=9+1/3






7 0
3 years ago
Please help please. I will mark brainlist
Alborosie

Answer:

I asked my teacher is she could help me and she said it was -7+10=3.       Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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