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vladimir1956 [14]
2 years ago
6

the combined area of two squares is 45 square cm. each side one square is twice as long as a side of the other Square. what is t

he length of each side of the larger square​
Mathematics
1 answer:
anygoal [31]2 years ago
4 0
6 centimeters



x will represent the side length of the smaller square, so 2x is the side length of the bigger square.

x*x + 2x*2x = 45

x^2 + 4x^2 = 45

5x^2 = 45

x^2 = 9 (Divide by 5)

sqrt(x^2) = sqrt(9)

x = 3

2x = 6 (Multiply by 2)



Please consider marking this answer as Brainliest to help me advance.
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a farmers packs 46 apples into trays for market.Each tray holds 6 apples.how many apples are in partially filled tray
denis23 [38]
46 - 6 - 6 - 6 - 6 - 6 - 6-6=46-(7)(6)=46-42 = \boxed {4}
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What is the slope of 2,000=20×+10y?
sergiy2304 [10]
Y=-2x+200 hope this helps
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Read 2 more answers
Fill in the table using this function rule. y=-3x-3 ​
pashok25 [27]

Answer:

When x = -2, y = 3

When x = -1, y = 0

When x = 0, y = -3

When x = 1, y = -6

Step-by-step explanation:

Given:

y = -3x - 3

Fill in the table using the following value for x

When x = -2

y = -3x - 3

y = -3(-2) - 3

y = 6 - 3

y = 3

When x = -2, y = 3

When x = -1

y = -3x - 3

y = -3(-1) - 3

y = 3 - 3

y = 0

When x = -1, y = 0

When x = 0

y = -3x - 3

y = -3(0) - 3

y = 0 - 3

y = -3

When x = 0, y = -3

When x = 1

y = -3x - 3

y = -3(1) - 3

y = -3 - 3

y = -6

When x = 1, y = -6

3 0
2 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
Someone pls help me i really need this
lukranit [14]
Y=1\2x.
hopes this helps you
5 0
2 years ago
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