Answer:

Step-by-step explanation:

Adding and Subtracting 1 to the Numerator

Dividing Numerator seperately by 

Here integral of 1 is x +c1 (where c1 is constant of integration
----------------------------------(1)
We apply method of partial fractions to perform the integral
=
------------------------------------------(2)

1 =
-------------------------(3)
Substitute x= 1 , -1 , i in equation (3)
1 = A(1+1)(1+1)
A = 
1 = B(-1-1)(1+1)
B = 
1 = C(i-1)(i+1)
C = 
Substituting A, B, C in equation (2)
= 
On integration
Here 
=
-
-
+ c2---------------------------------------(4)
Substitute equation (4) back in equation (1) we get

Here c1 + c2 can be added to another and written as c
Therefore,

Hey there!
When multiplying variables with the same degree, be sure to add the two degrees being multiplied.
For example;
x * x; both of these terms have the degree of "1" as they are "x^1". Since we are multiplying them, we need to add their degrees.
x^1 * x^1 = x^2
Now that we've broken down what we are doing, let's apply this new knowledge to your problem.
(x^3)(x^-2); Remember to just add the degrees; -2 + 3 = 1
This means our product is x^1, or just x.
I hope this helps!
Express 0.31 as a fraction and express 0.2 as a fraction
Slope formula: Change in y over change in x
Change in y: +4
Change in x: +5
Slope: 4/5
Hope this helps :)
Please give brainliest
Answer:
$31728
Step-by-step explanation:
sorry if I'm wrong