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3 years ago

Heyyyyy can you please help me do this ?!

Mathematics

1 answer:

Naddika [18.5K]3 years ago

6 0

Answer:

3u+12

Step-by-step explanation:

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PLEASE HELP!!

miskamm [114]

Answer: Choice A. 4 times

========================================================

Explanation:

We'll be using this formula

$m = \frac{f(b)-f(a)}{b-a}$

to compute the average rate of change (AROC) from x = a to x = b. Note how this is effectively the slope formula because y = f(x).

To start things off, we'll compute the AROC from x = 1 to x = 2.

$m = \frac{g(b)-g(a)}{b-a}\\\\m = \frac{g(2)-g(1)}{2-1}\\\\m = \frac{5(2)^2-5(2)^1}{2-1}\\\\m = \frac{10}{1}\\\\m = 10\\\\$

Do the same for the AROC from x = 3 to x = 4.

$m = \frac{g(b)-g(a)}{b-a}\\\\m = \frac{g(4)-g(3)}{4-3}\\\\m = \frac{5(2)^4-5(2)^3}{4-3}\\\\m = \frac{40}{1}\\\\m = 40\\\\$

The jump from m = 10 to m = 40 is "times 4", which is why choice A is the final answer.

7 0

3 years ago

John traveling to a meeting that is the 28 miles away he needs to be there in 30 min,how fast does he need to go to make it to t

Degger [83]

Answer:

30 mph

Step-by-step explanation:

3 0

2 years ago

The difference of 3/8 of 1/2 and 3/4 of 1/3

Rainbow [258]

Answer:

difference between 3/8 and 1/2 is 1/8

difference between 3/4 and 1/3 is

5/12 i believe

Step-by-step explanation:

just change to common denominator and find the difference

5 0

3 years ago

2. Harry just deposited $1500 into a savings account giving 6% interest compounded quarterly.a) How much will be in the account

Studentka2010 [4]

The formula for compound interest is:

$\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{where,} \\ A=\text{ Final amount} \\ r=\text{ Interest rate} \\ n=\text{ Number of times interest applied per period} \\ t=\text{ Number of time period elapsed} \\ P=\text{ Intial principal balance} \end{gathered}$

Given data:

$\begin{gathered} P=\text{ \$1500} \\ r=6\text{ \%}=0.06 \\ n=4\text{ times (compounded quarterly)} \end{gathered}$

a. After ten years, that is t = 10 years, the amount in the account will be

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times10} \\ A=\text{ }1500(1+0.015)^{40} \\ A=\text{ }1500(1.015)^{40} \\ A=\text{ \$2721.03} \end{gathered}$

b. After twenty years, that is t = 20 years, the amount in the account will be:

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times20} \\ A=1500(1.015)^{4\times20} \\ A=1500(1.015)^{80} \\ A=\text{ \$}4935.99 \end{gathered}$

c. The time it takes for Harry's initial account value to double will be:

$\begin{gathered} A=2\text{ x initial value = 2 }\times\text{ \$1500 = \$3000} \\ 3000=1500(1.015)^{4t} \\ (1.015)^{4t}=\frac{3000}{1500} \\ (1.015)^{4t}=2 \\ \text{ Find the logarithm of both sides} \\ \ln (1.015)^{4t}=\ln 2 \\ 4t=\frac{\ln 2}{\ln 1.015} \\ 4t=46.56 \\ t=\frac{46.56}{4}=11.64 \end{gathered}$

Therefore, the time it takes Harry's initial account to double is approximately 11 years

8 0

1 year ago

Variation table of this <br> g(x)=2x^3 -x^2 -4x +6

Mrac [35]

Answer:

$2x^{3} - x^{2} - 4x +6$

2x-x-4 $x^{3-2}$ + 6

-3x+6

7 0

2 years ago