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konstantin123 [22]
3 years ago
6

For each of the compounds, find the length of the longest carbon chain in the box provided.

Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer: -

The first compound is 3-Methylheptane.

The second compounds is 4-ethyl-3-methyl-4-propylheptane

The 3rd one is propanol.

The 4th one is 2-propanol.

The 5th one is methoxyethane

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Which statement best explains why heating a liquid affects its viscosity?
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Answer:

A

Explanation:

took test I'm pretty sure and found respond else where

5 0
3 years ago
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Need help guys!!!!
Serhud [2]
A. When two chemicals mix their temperature rise: <span>Exothermic
b. </span>A solid burns brightly and releases heat, light and sound: <span>Exothermic
c. </span>When two chemicals are mixed their temperature drops: <span>Endothermic
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4 years ago
Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co
Anna11 [10]

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

6 0
3 years ago
A gardener cut her finger while pruning shrubs. She noticed that after two weeks the wounds had nearly healed with just a small
kkurt [141]

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c

Explanation:

7 0
3 years ago
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A reaction occurs in a calorimeter that heats up 15g water from 25 oC to 50 oC. The specific heat of water is 4.184 J/goC. Deter
Anit [1.1K]

The thermal energy (Q) needed : = 1882.8 J

<h3>Further explanation</h3>

Given

15g water from 25 °C to 50 °C

Required

The thermal energy (Q)

Solution

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Input the value :

Q = 15 g x 4.184 J/g°C x (50 °C- 20 °C)

Q = 1882.8 J

7 0
3 years ago
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