The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.
Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.
We recognise that
h * 2 = PT - P * h * 20 = 1atm - 0.037atm
= 0.963 atm
1 * h * 2 = Ph * 2V / R * T
= 0.963 atm x 0.520 L / 0.0821 L atm/
molK * 301
= 0.02 mol h2
= 0.02molZn
So 0.02 mol Zn x 65.39 g/mol
= 1.33 g Zn
Read more about zinc;
brainly.com/question/28880469
#SPJ4
Answer: Contamination
Explanation: This is a known contrainst when performing transformation in the lab. Normally the Pglo plasmid asides glowing under UV, possess a Amp gene that codes for resistance to the antibiotics Ampicillin. Transform cells will survive while untransformed cells will normally die. If untransformed (non glowing, non Ampicillin resistant) cells thrive in the medium, it is definitely a case of contamination. Start again but this time, disinfect appropriately bad be cautious of any potential contamination.
Answer:
the answer should be: 12.00 Mol KCIO³ × 3 Mol 0² divided by 2 mol KCIO³ = 18.00 mol 0²
Metallic (w) with a boiling point of 566”
Answer:
The particles in the water are always moving
Explanation: