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3 years ago

What is this answer??24 x 18 (Show your work)

Mathematics

2 answers:

nikdorinn [45]3 years ago

8 0

24
x18
____

8 x 4 = 32
8 x 2 = 16

remember to carry

1 x 4 = 4
1 x 2 = 2

then add..

final answer is 432

pochemuha3 years ago

6 0

24
18×
192
24 plus

equal to 432

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Math help please help thanks

ser-zykov [4K]

Answer:

Step-by-step explanation:

Draw a line from the bottom of the 4 foot line straight across (horizontally) until it hits the vertical line on your left.

The two lines (the one you drew and the left vertical line) meet at right angles.

The upper figure is a rectangle.

Area = L * W

L = 5

W = 4

Area = 5 * 4

Area = 20

Now the bottom rectangle can be found the same way.

Area = L * W

L = 14

W = 3

Area = 14 * 3

Area = 42

The total area = 42 + 20

Total area = 62.

The comment was correct.

5 0

3 years ago

Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

3 years ago

An online store lets customers have their name printed on any item they buy. the total cost c in dollars is the price of the ite

Vsevolod [243]

So the total cost depends on the price of the item(s) (c depends on p)
The independent variable is p, the price of the item, because it is not going to depend on anything else.
The dependent variable is c, because the total cost depends on how many items there are, whether your name is marked on it, etc.
The equation would be :
c = p + $3.99

I hope this was helpful!

4 0

3 years ago

Oh my life found out I have more homework help

Triss [41]

1. 8(-18d-10) = -144d-80

2. -13+14(-18+10d) = -13-252+140d = -265+140d

3. 15(-7x-3) = -105x-45

The number are quite weird but we have to deal with them.

6 0

3 years ago

Read 2 more answers

F(x)=(x-6)e^-3x find the interval in which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema

Over [174]

$\bf f(x)=(x-6)e^{-3x}\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)]
\\\\\\
\cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}$

set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there

there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema

5 0

3 years ago