Question

2 in 1. Intermediate Algebra

Answer 1

So the first one is (7x)^(1/2) or square root of 7x minus - 5 square root all squared so

([7x^(1/2)]-[5^(1/2)]) times ([7x^(1/2)]-[5^(1/2)])

or 7x-(35x^(1/2))-5+(35x^(1/2)) or 7x-5

number 2
since 11 is 1/2 of 22 it can be written as 

the square root of 3 or 3^(1/2)