Answer: 18 pages
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Explanation:
Trey reads 10 pages in 25 minutes, which means we have the ratio
10 pages: 25 minutes
Divide each part of the ratio by 25
10 pages: 25 minutes
10/25 pages: 25/25 minutes
0.4 pages: 1 minute
So Trey's unit rate is 0.4 pages per minute. In one minute, Trey reads 0.4 of a page
Now multiply both sides of the last ratio by 45
0.4 pages: 1 minute
45*0.4 pages: 45*1 minute
18 pages: 45 minutes
Which is why the answer is 18 pages
It takes Trey 45 minutes to read 18 pages
Or in other words, Trey reads 18 pages in 45 minutes.
Answer:
1. 0
2. 18 th term
3. 209
4. 670
Step-by-step explanation:
1. n^th term of an A.P = a + (n - 1)d , where n is the term
6 = a + (5 - 1)d ... (i)
5 = a + (6 - 1)d ... (ii)
a + 4d = 6 ... (i)
a + 5d = 5 ... (ii)
Subtracting (ii) - (i) we get;
0 + d = -1 , d = -1
So the common difference (d) = -1
And first term (a);
a + 4(-1) = 6
a = 6 + 4 = 10
11^th term will be;
= 10 + -1(11 - 1) = 10 - 10 = 0
2. The A.P is;
1, 4, 7, 10, 14, ....
The first term (a) = 1
The common difference (d) = 3
= a + (n - 1)d
52 = 1 + (n - 1)3
3n - 3 + 1 = 52
3n = 52 + 2 = 54
n = 54/3 = 18 th term
3. The A.P is;
4, 9, 14, ... , 254
The first term (a) = 4
The common difference (d) = 5
= a + (n - 1)d
To find what term number 254 is;
254 = 4 + (n - 1)5
5n - 5 + 4 = 254
5n = 254 + 1 = 255
n = 255/5 = 51
The 10^th term from the end of the AP is the 42^nd term.
= 4 + (42 - 1)5 = 4 + 205 = 209
4. The A.P is;
5, 8, 11, 14, ...
The first term (a) = 5
The common difference (d) = 3
Sum of n terms in an A.P is given by;
=
(2a + (n - 1)d)
=
(10 + 19(3) = 10(10 +57) = 670
Answer:
The standard deviation reduces when sample size (n) increases
Step-by-step explanation:
From the above information given, we have that mean = 75.5
Standard deviation = 3.5
But Standard deviation = √summation (x-u)/n
This simply implies that when sample (n) is increased there would be a reduction in the standard deviate.
Answer:
According to steps 2 and 4. The second-order polynomial must be added by
and
to create a perfect square trinomial.
Step-by-step explanation:
Let consider a second-order polynomial of the form
,
. The procedure is presented below:
1)
(Given)
2)
(Compatibility with addition/Existence of additive inverse/Modulative property)
3)
(Compatibility with multiplication)
4)
(Compatibility with addition/Existence of additive inverse/Modulative property)
5)
(Perfect square trinomial)
According to steps 2 and 4. The second-order polynomial must be added by
and
to create a perfect square trinomial.