The runner's acceleration during this time interval is 10
<u>Given the following data:</u>
- Initial velocity, U = 0 m/s (since the sprinter is starting from rest).
- Final velocity, V = 10.0 m/s
To calculate the runner's acceleration during this time interval, we would use the first equation of motion;
Mathematically, the first equation of motion is calculated by using the formula;
<u>Where:</u>
- U is the initial velocity.
- t is the time measured in seconds.
Substituting the given parameters into the formula, we have;
Therefore, the runner's acceleration during this time interval is 10
Read more: brainly.com/question/8898885
Answer:
The Work-in-Process limit at the Analyzing step of the Program Kanban is based on the overall availability of Product Management, other subject matter experts, and the available development capacity and the VA time percentage of each process.
Explanation:
The term work-in-progress (WIP) describes partially finished goods or raw materials, labor, and overhead costs at several stages of the production process to be completed in a production and supply-chain management . WIP (Work in Progress) limits restrict and balance, through kanban board columns,the amount of production to match demand to capacity so workflow is increased all along the line helping it to finish faster avoiding bottlenecks focusing only on current tasks without new work taken on.
A Kanban board requires knowledge to provide a clear view of the WIP limit reached point but it also requieres discipline and commitment from employees.
Answer:
s = 1800 m = 1.8 km
Explanation:
The distance, the speed, and the time of reach of the sound are related by the following formula:
where,
s = distance
v = speed
t = time
FOR WATER:
---------------------- eq (1)
where,
s = distance between ship and diver = ?
= speed of sound in water = 1440 m/s
t = time taken by sound in water
FOR AIR:
---------------------- eq (2)
where,
s = distance between ship and diver = ?
= speed of sound in water = 344 m/s
t + 4 s = time taken by sound in water
Comparing eq (1) and eq (2),because distance remains constant:
t = 1.25 s
Now using this value in eq (1):
<u>s = 1800 m = 1.8 km</u>
Answer:
Explanation:
When the spring is compressed by .80 m , restoring force by spring on block
= 130 x .80
= 104 N , acting away from wall
External force = 82 N , acting towards wall
Force of friction acting towards wall = μmg
= .4 x 4 x 9.8
= 15.68 N
Net force away from wall
= 104 -15.68 - 82
= 6.32 N
Acceleration
= 6.32 / 4
= 1.58 m / s²
It will be away from wall
Energy released by compressed spring = 1/2 k x²
= .5 x 130 x .8²
= 41.6 J
Energy lost in friction
= μmg x .8
= .4 x 4 x 9.8 x .8
= 12.544 J
Energy available to block
= 41.6 - 12.544 J
= 29 J
Kinetic energy of block = 29
1/2 x 4 x v² = 29
v = 3.8 m / s
This will b speed of block as soon as spring relaxes. (x = 0 )
I’m guessing b because hydrogen is in your room and maybe eliminate to o but it also can be D
my final is: B!