A straight wire in a magnetic field experiences a force of 0.030 N when the current in the wire is 2.7 A. The current in the wir e is changed, and the wire experiences a force of 0.047 N as a result. What is the new current?
1 answer:
Answer:
current is 4.23 A
Explanation:
Given data
force f1 = 0.030 N
current I = 2.7 A
force f2 = 0.047 N
to find out
the new current
solution
we know that force = flux density(B) × current(I) × length(L) ...............1
f1 = BL × current
so BL = 0.030/ 2.7 = 0.011111
now put BL and f2 in equation 2 we get current
force = flux density(B) × current(I) × length(L)
0.047 = 0.01111 × current
current = 0.047 / 0.01111
current is 4.23 A
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