Answer:
Explanation:
mass of liquid m₁ = 161 g
temperature t₁ = 31.8
final temperature t₂ = 28.8
Let m g of ice melted to cool the liquid
heat gained = mass x latent heat of fusion + mass x loss of temp x s heat of water
= m x 80 + m x 1 x ( 31.8 - 28.8 ) ( latent heat of ice = 80 cals/g )
= 83 m
heat lost = 161 x 1 x ( 31.8 - 28.8 ) ( specific heat of water = 1 cal / g / k )
= 161 x 3
heat lost = heat gained
83 m = 161 x 3
m = 5.82 g
mass of remaining ice = 131 - 5.82
= 125.18 g
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