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3 years ago

Asteroid A has 3.5 times the mass and 2.0 times the velocity of Asteroid B. If

Physics

1 answer:

kaheart [24]3 years ago

8 0

Answer:

K_A = 32.2 10⁶ J

Explanation:

In this exercise we must relate the quantities given to find the kinetic energy

Asteroid A data

m_A = 3.5 m_B

v_A = 2.0 v

they also give the value of the kinetic energy of asteroid A

K_B = 2.3 10⁶ J

the expression for scientific energy is

K = ½ m v²

let's replace

K_A = ½ m_a V_a2

K_A = ½ 3.5 m_B (2.0 v_B)^2

K_A = 3.5 2² (½ m_B v_B²)

K_A = 14 K_B

K_A = 32.2 10⁶ J

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Answer:

$A. 8.29\times 10^{-18}\ J$

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$U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J$

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3 years ago

According to Binet, mental age relates to chronological age because ___________.

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3 years ago

The current theory of the structure of the

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1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

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We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

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So, the speed is:

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So, we can now find the kinetic energy:

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Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

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where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

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Learn more about kinetic energy:

brainly.com/question/6536722

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