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Daniel [21]
3 years ago
15

How to prove the converse to the same side interior angles theorem

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer:If two lines are cut by a transversal and the consecutive interior angles are supplementary ...

Step-by-step explanation:

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jack wants to run at least 275 miles before the baseball season begins. he has already run 25 miles. he plans to run 2.5 miles e
d1i1m1o1n [39]

Hey there! I'm happy to help!

We see that Jack has already run 25 miles.

25

He also wants to run 2.5 miles every day. This means we will multiply 2.5 miles by the number of days he runs. We will call the number of days x.

25+2.5x

And he needs this to equal 275.

25+2.5=275

We subtract 25 from both sides.

2.5x=250

We divide both sides by 2.5

x=100

So, Jack will need to run 100 days to meet his goal.

Have a wonderful day and keep on learning! :D

7 0
3 years ago
A Rectangle with sides 100m and 50m. Person B and Person A start walking in the opposite direction at the same point with veloci
Maurinko [17]

Answer:

It takes takes them 31.67 secs to meet after Person A starts walking

OR

34.67 secs after Person B starts walking

Step-by-step explanation:

First, we will find the perimeter of the rectangle

From,

Perimeter of rectangle = 2 (l + b)

Where l is the length

and b is the breadth

From the question, l = 100m

and b = 50m

Hence,

Perimeter of the rectangle = 2 (100+50)

= 2(150) = 300m

Hence, the perimeter of the rectangle is 300m

This is the total distance that will be covered by both persons by the time they meet.

Let the distance covered by person A be S_{1}

and the distance covered by person B be S_{2}

We can write that

S_{1} + S_{2} = 300m

Velocity of person A, V_{A} = 4 m/s

and velocity of person B, V_{B} = 5 m/s

From the question, Person A starts walking 3 seconds after person B,

This means, if person A spends t secs before they meet, then person B would spend (3 + t) secs.

For Person A,

Velocity = 4 m/s

Time = t secs

Distance = S_{1}

From,

Velocity = \frac{Distance}{Time}

Then,

Distance = Velocity \times time

S_{1} = 4 \times t

S_{1} = 4t ...... (1)

For Person B

Velocity = 5 m/s

Time = (t + 3) secs

Distance = S_{2}

Also, from

Distance = Velocity \times time

S_{2} = 5 \times (3+t)

S_{2} = 5(3+t) ...... (2)

Recall that, S_{1} + S_{2} = 300m

Then, S_{2} = 300m - S_{1}

We can then write that,

300m - S_{1} = 5(3+t)

Then,

S_{1} = 300 - 5(3+t) ..... (3)

Equating equations (1) and (3), we get

300 - 5(3+t) = 4t

300 - 15 -5t = 4t\\9t = 285\\t = \frac{285}{9}\\

t = 31.67 secs

This is the time spent by Person A

Hence, it takes takes them 31.67 secs to meet after Person A starts walking OR

34.67 secs after Person B starts walking

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The following is most likely the next step in the series?
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The answer is A :) The line is moving clockwise. Imagine it’s going from 3pm, to 6pm, to 9pm....the next is 12am!
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