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tatiyna
2 years ago
6

Select the equation in which the graph of the line has a negative slope, and the y-intercept equals 50.

Mathematics
2 answers:
Aleks04 [339]2 years ago
8 0
Convert each one to the  form y = mx + b   where m=slope and b = y-intercept.

(a) 5y = 10x - 40

y = 2x -  8         m= 2 (positive slope) and  y-intercept = -8 so its not (a)
zepelin [54]2 years ago
8 0

Answer:

The answer that represent a negative slope and a y-intercept 50 is letter C.

Step-by-step explanation:

The answers are represented like a general equation Ax + By + C = 0, so you need to clear "y" to find slope-intercept form of a line y=mx+b, where m is the slope and b is the intercept, so if you clear:

a) y = (10x - 40)/5 .... in this ecuation the slope is positive and the ininterception 40 negative.

b) y = (5x +12)/10 .... in this ecuation the slope is positive and the interception 12 positive.

d) y= (x-10)/2 .... in this ecuation the slope is positive and the interception 10 negative.

c) y = 50 - 5x, in this ecuation the slope is negative, and the interception 50 positive, so this is the correct answer.

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For this case we have the following quadratic equation:

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Its roots will be given by:

w = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\w = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (6) (- 20)}} {2 (6)}\\w = \frac {7 \pm \sqrt {49 + 480}} {12}\\w = \frac {7 \pm \sqrt {529}} {12}\\w = \frac {7 \pm23} {12}

The roots are:

w_ {1} = \frac {7 + 23} {12} = \frac {30} {12} = \frac {15} {6} = \frac {5} {2}\\w_ {2} = \frac {7-23} {12} = \frac {-16} {12} = - \frac {8} {6} = - \frac {4} {3}

Answer:

w_ {1} = \frac {5} {2}\\w_ {2} = - \frac {4} {3}

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