All categories

3 years ago

Select the equation in which the graph of the line has a negative slope, and the y-intercept equals 50.

2 answers:

8 0

Convert each one to the form y = mx + b where m=slope and b = y-intercept.

(a) 5y = 10x - 40

y = 2x - 8 m= 2 (positive slope) and y-intercept = -8 so its not (a)

zepelin [54]3 years ago

8 0

Answer:

The answer that represent a negative slope and a y-intercept 50 is letter C.

Step-by-step explanation:

The answers are represented like a general equation Ax + By + C = 0, so you need to clear "y" to find slope-intercept form of a line y=mx+b, where m is the slope and b is the intercept, so if you clear:

a) y = (10x - 40)/5 .... in this ecuation the slope is positive and the ininterception 40 negative.

b) y = (5x +12)/10 .... in this ecuation the slope is positive and the interception 12 positive.

d) y= (x-10)/2 .... in this ecuation the slope is positive and the interception 10 negative.

c) y = 50 - 5x, in this ecuation the slope is negative, and the interception 50 positive, so this is the correct answer.

You might be interested in

Hey!

noname [10]

Answer:

A. Cylinder + cone

Volume is the sum of volumes:

V = Vcon + Vcyl = 1/3πr²h₁ + πr²h₂
V = 1/3π*9²*12 + π*9²*120 = 31554.2 cm³

Surface area of cone:

A = A=πr(r+√(h₁²+r²)) = π*9(9 + √(9²+12²)) = 678.6 cm²

Surface area of cylinder minus bases:

A = 2πrh₂ = 2π*9*120 = 6785.8 cm²

Total surface area:

678.6 + 6785.8 = 7464.4 cm²

-------------------------------------------------

B. Cube+ pyramid

Volume:

V = a³ + (1/3)a²h = a³ + (1/3)a²√(l²-(a/2)²)
V = 8³ + (1/3)8²√(10²-4²) = 707.5 cm³

Surface area of pyramid:

A = a² + 2al = 8² + 2*8*10 = 224 cm²

Surface area of cube minus bases:

A = 4a² = 4(8²) = 256 cm²

Total surface area:

A = 224 + 256 = 480 cm²

5 0

3 years ago

Please help me answer this question

avanturin [10]

By direct substitution and simplification, the trigonometric function z = cos (2 · x + 3 · y) represents a solution of the partial differential equation $\frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z$ .

<h3>How to analyze a differential equation</h3>

Differential equations are expressions that involve derivatives. In this question we must prove that a given expression is a solution of a differential equation, that is, substituting the variables and see if the equivalence is conserved.

If we know that $z = \cos (2\cdot x + 3\cdot y)$ and $\frac{\partial^{2} t}{\partial x^{2}} - \frac{\partial^{2} t}{\partial y^{2}} = 5\cdot z$ , then we conclude that:

$\frac{\partial t}{\partial x} = -2\cdot \sin (2\cdot x + 3\cdot y)$

$\frac{\partial^{2} t}{\partial x^{2}} = - 4 \cdot \cos (2\cdot x + 3\cdot y)$

$\frac{\partial t}{\partial y} = - 3 \cdot \sin (2\cdot x + 3\cdot y)$

$\frac{\partial^{2} t}{\partial y^{2}} = - 9 \cdot \cos (2\cdot x + 3\cdot y)$

$- 4\cdot \cos (2\cdot x + 3\cdot y) + 9\cdot \cos (2\cdot x + 3\cdot y) = 5 \cdot \cos (2\cdot x + 3\cdot y) = 5\cdot z$

To learn more on differential equations: brainly.com/question/14620493

#SPJ1

3 0

2 years ago

Can someone show me the work for this?

Leya [2.2K]

We are given the equation or function y = sqrt (2x + 1). The derivative of the equation is expressed as

1. dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
when x = 4 and dx/dt =3
dy/dt = 0.5 *2 *3*(2*4 + 1)^-0.5
dy/dt = 1

2. dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
 If dy/dt = 5, find dx/dt when x = 12.
 5= 0.5 *2 (2*12 + 1)^-0.5 dx/dt
dx/dt = 1

7 0

3 years ago

The elevation of a toy glider changes by -19.5 centimeters in 3 seconds.

svlad2 [7]

Answer:

Step-by-step explanation:

I have bin trying to get the answer

6 0

3 years ago

Read 2 more answers

Please help me please please thank you

OleMash [197]

9514 1404 393

Answer:

see below

Step-by-step explanation:

The idea is you're trying to find quotient values that get you close to the dividend value when they're multiplied by the divisor.

In the left panel, you are basically looking at 8/3 ≈ 2. Since that is 8 tens, the partial quotient is 2 tens, or 20. The value of that multiplied by the divisor (3) is what gets subtracted from 87 for the next effort.

That difference (27) is the new dividend at the top of the right panel. The line below it (-27) is the result of multiplying the partial quotient by 3. Hence, that partial quotient on the top line must be 9. We want the difference at the bottom of the right panel to be zero.

In case you didn't know already that 87/3 = 29, you could work backwards. Starting from 0 at the bottom right, you would fill in the boxes above that, then copy the top box in that panel (27) to the difference at the bottom of the left panel. Of course, the middle number there must be 60 for the difference to be 27. That is 3·20, meaning the partial quotient at left on the top line is 20.

4 0

3 years ago