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3 years ago

What is (3-6)/8-2+7/2

1 answer:

5 0

(3-6)/(8-2)+(7/2)
Do what is in the parenthesis first.
-3/6+3.5
-0.5+3.5=3

Therefore, your answer is 3
Hope this Helps!

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Evaluate using integration by parts

PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

$I(n)=\displaystyle\int x^ne^x\,\mathrm dx$

One round of IBP, setting

$u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx$

$\mathrm dv=e^x\,\mathrm dx\implies v=e^x$

gives

$\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx$

$I(n)=x^ne^x-nI(n-1)$

This is called a power-reduction formula. We could try solving for $I(n)$ explicitly, but no need. $n=5$ is small enough to just expand $I(5)$ as much as we need to.

$I(5)=x^5e^x-5I(4)$

$I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)$

$I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)$

$I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)$

$I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))$

Finally,

$I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C$

so we end up with

$I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C$

$I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C$

and the antiderivative is

$\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C$

8 0

3 years ago

Round 4.645 to the<br> nearest whole number.

jeka94

5. since .6 is greater than 5, we round up.

7 0

3 years ago

Read 2 more answers

What is the product of 14560 times 10

Andrews [41]

The product of 14560 and 10 is 145600

3 0

3 years ago

Michael sold his painting for $50. He sold his painting for $10 less than its original price. At what price did Michael buy the

netineya [11]

It would be 60. He sold his painting for 50 which was 10 less that the original price. So 50+10=60

7 0

3 years ago

Read 2 more answers

PLEASE HELPPP MEEEEEEEEEEE I DK THIS-

Julli [10]

Answer:

FOr the first one you can do:

y= -x +4

y= -x+2

y = -x

y= -x-2

y = x-4

Step-by-step explanation:

I'll do the second one in a different answer use these for now.

8 0

2 years ago