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2 years ago

Can anyone help me please

Mathematics

1 answer:

Xelga [282]2 years ago

3 0

popopoppopopoopopopp[poopopopopopop

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7) Which statement about perpendicular lines is true?

agasfer [191]

Answer:

is the a. Perpendicular lines form 90° angles.

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1 year ago

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write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

2 years ago

Please help me!!!!!!!

Pie

Answer:

7 0

3 years ago

I need help with this it's urgent!

borishaifa [10]

Oh shucks man, I'm sorry bout that

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2 years ago

Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and pe

Pavel [41]

See the picture to better understand the problem

we know that
in the triangle ABC
∠A+∠B+∠C=180°
find ∠C
∠C=180-[80+65]------> ∠C=35°

Applying the law of sines

AB/sin C=CB/sin A
solve for CB
CB=AB*sin A/sin C-----> CB=45*sin 65/sin 35-----> CB=71.10 ft

the answer is
<span>the distance from person B to the top of the hill is 71.10 feet</span>

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2 years ago

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