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Otrada [13]
3 years ago
6

Lavinia has 9 glasses and 6 mugs . she would like to set them out in identical groups with none left over in preparation for a p

arty. What is the greatest number of groups Lavinia can set out
Mathematics
2 answers:
sveticcg [70]3 years ago
6 0

Answer:

The greatest number of groups Lavinia can set out is:

3

Step-by-step explanation:

Lavinia has 9 glasses and 6 mugs .

We know that:

9=3×3

and 6=3×2

So, maximum 3 groups can be set out which contains 3 glasses and 2 mugs each

Hence,  the greatest number of groups Lavinia can set out is:

3

sergejj [24]3 years ago
3 0
You must find the factors of each number...
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6

Next, determine the common multiple...
9 = 1, 3, 3, 9
6 = 1, 2, 3, 6

Therefore, the most groups Lavinia can make without any glasses or mugs left to spare is 3.
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Answer:

2)

(2x -5) + (x) + (2x - 3) = 32.

5x-8 = 32.

ii) 5x-8=32

5x= 32+8

5x = 40

x= 40/5

x = 8

iii) 2x -5

2 × 8 -5 = 11.

2x-3

2×8-3

16-3 = 13

x =8

sides of the triangle= 8, 11, 13.

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3 years ago
90/110 reduce the fraction
IrinaVladis [17]
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3 years ago
A) how many 3/5s are in 1<br> b) use the answer to part A to find the number of 3/5s in 2
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3 years ago
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5. Draw the number line graph of -3.
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3 years ago
Solve the equation by using the quadratic formula.<br> 8x2 – 2x - 15 =0
ddd [48]

Answer:

x = 3/2 or x = -5/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 2 x - 15 = 0

Using the quadratic formula, solve for x.

x = (2 ± sqrt((-2)^2 - 4×8 (-15)))/(2×8) = (2 ± sqrt(4 + 480))/16 = (2 ± sqrt(484))/16:

x = (2 + sqrt(484))/16 or x = (2 - sqrt(484))/16

Simplify radicals.

sqrt(484) = sqrt(4×121) = sqrt(2^2×11^2) = 2×11 = 22:

x = (2 + 22)/16 or x = (2 - 22)/16

Evaluate (2 + 22)/16.

(2 + 22)/16 = 24/16 = 3/2:

x = 3/2 or x = (2 - 22)/16

Evaluate (2 - 22)/16.

(2 - 22)/16 = -20/16 = -5/4:

Answer: x = 3/2 or x = -5/4

4 0
2 years ago
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