The correct answer for the given statement above would be TRUE. It is true that there is no solution to the equation sec x = 0. Why?
<span>Sec(x) is actually 1/cos(x), which can't be absolute zero. Cos(x) ranges between -1 and 1; it would have to be unbounded for sec(x) to reach 0, or in short, it is undefined. Hope this answer helps. </span>
Answer:
Step-by-step explanation:
I do not now what you mean?
Answer:
Value is x=8 and y=4
Step-by-step explanation:
Given : A right triangle 'A' hypotenuse length of x+4 and a leg of x,
and right triangle 'B' hypotenuse length of 3y and a leg length of y+4
To find : For what values of x and y are the triangles congruent by HL?
Solution :
Triangle A,
Hypotenuse: x+4
Leg: x
Triangle B,
Hypotenuse: 3y
Leg: y+4
Since the triangle A and B are congruent so, the sides of triangles are equal.
(Hypotenuse are equal) ..........[1]
and
(Legs are equal) ..........[2]
Solving the equation of system,
Put the value of x from [2] in [1],




Substitute y in [2],
Therefore, The value of x=8 and y=4
Verifying for the values of x and y:
Triangle A,
Hypotenuse: x+4=8+4=12
Leg: x=8
Triangle B,
Hypotenuse: 3y=3(4)=12
Leg: y+4=4+4=8
Both hypotenuses and both legs are equal hence they are congruent.
a)
because it is equal to the area of the shaded region between X=4 and X=6, and the probability that X falls within some interval is given by the area under the PDF.
b)
because the shaded region is a rectangle of height 1/5 (by virtue of X following a uniform distribution over the interval [2, 7], which has length 5).