Question

16(6−5x)^2+17=42 Please solve for all the possible solutions to x.

Answer 1

Answer: $x=19/20$ $or$ $x=29/20$

Simplify both sides of the equation

$400x^2-960x+593=42$

Subtract 42 from both sides

$400x^2-960x+593-42=42-42\\400x^2-960x+551=0$

Factor left side of equation

$(20x-19)(20x-29)=0$

Set factors equal to 0

$20x-19=0$   $or$     $20x-29=0$

$x=19/20$    $or$     $x=29/20$