Question

Vector makes three different purchases at three different stores one afternoon. Each time he spends 1/3 of the money he is carrying. If he ends the day with $16 how much money did he have at the end of the day?

Answer 1

Answer:

The money which vector have is $54

Step-by-step explanation:

Given as:

Vector makes three different purchases at three different stores one afternoon. Each time he spends 1/3 of the money he is carrying.

At The end of day vector have money left = $16

Let the money does Vector have at start = $x

Now, According to question

At The first store he had money with him = $x

So, After purchased of item, The money left with him = $x - $$\dfrac{x}{3}$ = $$\dfrac{2x}{3}$

At The second store he had money with him = $$\dfrac{2x}{3}$

So, After purchased of item, The money left with him = $$\dfrac{2x}{3}$  - $$\dfrac{2x}{9}$ = $$\dfrac{4x}{9}$

At The third store he had money with him = $$\dfrac{4x}{9}$

So, After purchased of item, The money left with him = $$\dfrac{4x}{9}$  - $$\dfrac{4x}{27}$ = $$\dfrac{8x}{27}$

Now, Again

∵ At The day end the money left with Vector = $16

So, $$\dfrac{8x}{27}$ = $16

Or. 8 x = $16 × 27

∴ x = $\frac{16\times 27}{8}$

i.e x = $54

So, The money which vector have = x = $54

Hence, The money which vector have is $54 Answer