We need to know some log properties
1. when the base is not stated, assume that it is base 10 or log₁₀
2.

-log(10^-1)=

answer is D. -1
Answer:
D) x = ± 2√5 - 4
Step-by-step explanation:
2x² + 16x - 8 = 0
Yah, i plugged this into m a t h w a y
(all of ur questions pretty much can use this app or website)
Answer:

Step-by-step explanation:
From inspection of the graph, we can see that the curve intercepts the x-axis at (-4, 0), (-1, 0) and (3, 0)
Therefore,
x = -4 ⇒ x + 4 = 0
x = -1 ⇒ x + 1 = 0
x = 3 ⇒ x - 3 = 0
Because (-4, 0) touches the x-axis, then (x + 4)² will be a factor
So (x + 4)², (x + 1) and (x - 3) are all factors of the polynomial

If we multiply the constants, this will give us the y-intercept:
⇒ 4² x 1 x -3 = -48
From inspection of the graph, the y-intercept is -6
So to get from -48 to -6 we need to multiply -48 by 1/8
Therefore, n = 1/8

Answer: a) 46 minutes
b) 10:47
The basic knowledge for this is that 60 minutes = 1 hour
<u>a)</u> Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes
Here you go! Total 46 minutes from Mosley to Bamford.
<u>b)</u> From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.
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hope it helped
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The area of the circle will be 28.27 km.