Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = 
~ N(0,1)
where, 
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( > 
) = P(Z > 1.25) = 1 - P(Z 
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
It is the second option, let me know if you got it right
Answer:
(22.12, 27.48)
Step-by-step explanation:
Given : Significance level : 
Sample size : n= 8 , which is a small sample (n<30), so we use t-test.
Critical values using t-distribution: 
Sample mean : 
Standard deviation : 
The confidence interval for population means is given by :-
i.e. 
Hence, the 95% confidence interval, assuming the times are normally distributed.= (22.12, 27.48)
Answer:
B. y = 
Step-by-step explanation:
I. Given x = 15 and y = 4
4 = 
4 = 2+2
4 = 4 true
II. Give x = 0 and y = 2
2 = 
2 = 0 + 2
2 = 2 true
III. Given x = -15 and y = 0
0 = 
0 = -2 + 2
0 = 0 true
Good luck.
Answer:
8
Step-by-step explanation:
3m + 9 -9m = 2m + 25
3m + 9 = 11m + 25
9 = 8m + 25
16/2 = 8m/2
M = 8
