Answer and Step-by-step explanation:
First of all lets define
X to be that the bags do contain large liquid amounts
+ to be that the test is not negative that is positive
From the question,
P(x) = 3/100 = 0.03
P(+|X) = 0.91
P(+|X′) = 0.05
Probability of bag having a positive test =p(+)
= P(+|X) (P(x)) + P(+|X′)(P(X′))
= P(X′)) = 1 – 0.03 = 0.97
Inserting these values into these formulas
0.91)(0,03) + (0.05)(0.97)
= 0.0273 + 0.0485
= 0.0758
The probability of the randomly selected bag having large liqid amount
= P(X|+) = (0.91*0.03)/(0.91*0.03)(0.05*0.97)
= 0.0273/0.0273+0.0485
= 0.0273/0.0758
= 0.3602
the probability that this bag does not have large liquid amount
= p(X'|+) = 1 - P(X|+)
= 1 - 0.3602
= 0.6398
1.2 e⁻¹¹
Because you need a number between 1 and 10 for scientific notation. So you move the decimal over 11 places. Since you move it to the right, it becomes a negative exponent.
Let's write 2 equations from the two statements given.
<em>Sarah spent 10 dollars on both oranges and apples</em>
<em />
Let the price of oranges be "x" and price of apples be "y", thus we can write:

Oranges cost 3 less than apples, thus we can say:

We can substitute this into the first equation and solve for y:

Thus, let's solve for x now,

We want the price of oranges (x), thus,
<em>Price of Oranges = $3.50</em>
Answer:
-3v
Step-by-step explanation:
-6v is a negative when 3v is positive
when you add 3v to -6v it equals -3v since 6 is greater
Answer:
5
Step-by-step explanation:
We are asked to find the value of A. We know from the question that we need to have the sum of -3x and (A)x equal the third term of the original polynomial, which is 2x. written out in an equation, it looks like this.

We can simplify the equation if we add 3x to both sides, which then leaves us with this.

We can further simplify the equation by dividing both sides by x. This leaves us with our last equation for this problem.

Finally, we have our answer. We can also verify that this is a valid integer by multiplying our, now completed, quotient by the divisor and adding the remainder, which in this case, our remainder is 0, so we will not be including it in our operation.

If our calculations were all correct, the product of these polynomials should equal our dividend, verifying our integer is valid; lo' and behold, it is.
