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Murrr4er [49]
3 years ago
11

Is there another way to write JK? Why or why not?

Mathematics
2 answers:
OleMash [197]3 years ago
5 0

Answer:

Just Kidding

Step-by-step explanation:

daser333 [38]3 years ago
4 0

Answer:

What do u mean

. I'm confused

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What is the vertex of the quadratic function y=-x²+6x+7? ​
vichka [17]

Answer:

(3,16)

Step-by-step explanation:

Factor the equation to find out that the roots are 7 and -1. The vertex's x will be in the center of these two points, so the center point between 7 and -1 is 3. Continue to substitute the x in the equation with 3 to get the other coordinate for vertex.

6 0
3 years ago
PLEASE HELP ASAP!!!!
Harlamova29_29 [7]

Answer:

D. y=\frac{1}{4}x

Step-by-step explanation:

3 0
3 years ago
Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
Circle A has a Circumference of approximately 314.159 feet. Circle B has a diameter that is half the size of Circle A. Which is
Kaylis [27]

The diameter of circle B is 50 cm.

Step-by-step explanation:

Given,

The circumference of circle A = 314.159 ft

Diameter of Circle B is half of the diameter of circle A.

Let, the radius of circle A is r

To find the diameter of circle B

Formula

Circumference of a circle of radius r = 2πr

According to the problem,

2πr = 314.159

or, r = \frac{314.159}{2X3.14}

= 50 (approx)

So,

The diameter of circle A = 2×50 cm = 100 cm

The diameter of circle B = 50 cm.

4 0
3 years ago
A magnitude 6.7 earthquake struck the SanFernando valley region of Los Angeles in 1994, causing widespread damage. Suppose anoth
madam [21]

Answer: 2.308 .

Step-by-step explanation:

Let X denotes the number of earthquakes in SanFernando valley region of Los Angeles in 1994.

Given: \mu=17.6

Probability is 0.87 that there will be at least 15 earthquakes .

i.e. P(X\geq15)=0.87

\Rightarrow\ P(\dfrac{X-\mu}{\sigma}\geq\dfrac{15-17.6}{\sigma})=0.87\\\\  \Rightarrow\ P(Z\geq\dfrac{-2.6}{\sigma})=0.87\ \ \ [Z=\dfrac{X-\mu}{\sigma}]

Z-value corresponding to p-value 0.87 is -1.1263 .

So, \dfrac{-2.6}{\sigma}=-1.1263

\sigma= \dfrac{-2.6}{-1.1263}\approx2.308

Hence, the required standard deviation = 2.308 .

4 0
3 years ago
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