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Aleksandr [31]
3 years ago
15

Progression I really need help with this ​

Mathematics
1 answer:
bija089 [108]3 years ago
6 0

Answer:

=x+2+x+3+2x-1

=x+x+2x+2+3-1

=4x+4

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
in 1990, the value of a home is $170,000. Since then, its value has increased 5% per year. what is the approximate value of a ho
Gwar [14]

value of home in 1991= 105% of 170000

value of home in 1992= 105%×105% of 170000

value of home in 1993= 105%×105%×105% of 170000

=$196,796.25

3 0
3 years ago
Deshawn leaves his house to run 5 miles. So
kow [346]

Answer:

He would need to run 7 more times to meet his goal of 5 miles

3 0
3 years ago
I need help on 27. Please help me! Answer the 2 questions- How does the expression compare? And who has more stamps? Tell me the
Norma-Jean [14]
100+ 100+ 100+ 9= 309
200+ 50 +50= 300
Petra has more stamps
3 0
3 years ago
Read 2 more answers
A pendulum clock is a clock that uses a swinging weight (a pendulum) as its
Gnoma [55]

Answer: x(t) = 5cm*cos(t*pi/2s)

Step-by-step explanation:

This is a sinusoidal equation, so we can write this as:

x(t) = A*cos(c*t + p)  + B

where B is the axis around the movement, as the resting position is x = 0, we have B = 0

so x(t) = A*cos(c*t + p)

A is the amplitude of the oscilation, c is the frequency and p is a phase.

We know that when t = 0s, we have x(2s) = 5cm

if this is the maximum displacement, then knowing that the maximum of the cosine is cos(0) = 1

then we must have that p = 0

x(0s) = A*cos(0) = 5cm

then we have A = 5cm

Now, when t = 2s, we have:

x(2s) = 5cm*cos(2s*c) = -5cm

then 2s*c is the minimum of the cos(x) function, this is:

cos(pi) = -1

then 2s*c = pi

c = pi/2s.

then our function is:

x(t) = 5cm*cos(t*pi/2s)

7 0
3 years ago
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