4 years ago

Progression I really need help with this

Mathematics

1 answer:

bija089 [108]4 years ago

6 0

Answer:

=x+2+x+3+2x-1

=x+x+2x+2+3-1

=4x+4

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yanalaym [24]

Answer:

It is b^6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π). (Enter your answers as a comma

Zina [86]

I'm assuming you meant:

$tan^{2}x + tanx - 30 = 0$
Let $u = tan(x)$

Thus, we can rewrite it into a quadratic.

$u^{2} + u - 30 = 0$
$(u + 6)(u - 5) = 0$
$u = -6 or u = 5$

Hence, $tan(x) = -6$ or $tan(x) = 5$
$x = tan^{-1}(-6)$ or $x = tan^{-1}(5)$

Rewriting it in general form, we get:
$x = \pi \cdot n + tan^{-1}(5), n \in Z$
$x = \pi \cdot n - tan^{-1}(6), n \in Z$

From there, you can find your solutions from $[0, 2\pi)$