Answer:
<em>42/63 = .6 repeating</em>
<em>30/38 = .625</em>
<em>36/60 = .6</em>
<em>57/90 = .63 repeating</em>
Step-by-step explanation:
Nd if I'm wrong then the 2nd nd 3rd one are switched
Answer:
i
Step-by-step explanation:
i
Csc theta=-2 then theta equals csc^-1(-2) then theta would equal 5pi/6, 7pi/6
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
