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TiliK225 [7]
3 years ago
6

Help!

Mathematics
1 answer:
EleoNora [17]3 years ago
8 0
Perimeter = lenght× 2 + width × 2
= 6 × 2 + 2 × 2
= 12 + 4
= 16
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What is the value of x????
inysia [295]

If QR is a median, then:

\dfrac{NO+MP}{2}=QR

We have NO = 30, MP = 9x - 42 and QR = x + 15. Substitute:

\dfrac{30+9x-42}{2}=x+15\qquad\text{multiply both sides by 2}\\\\9x-12=2x+30\qquad\text{add 12 to both sides}\\\\9x=2x+42\qquad\text{subtract 2x from both sides}\\\\7x=42\qquad\text{divide both sides by 7}\\\\\boxed{x=6}

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18.75 divided by 0.70
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RJ read 40 pages of gis book in 50 minutes. How many pages can I read in 80 minutes?
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alekssr [168]

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3 years ago
A can is 3" in diameter and 7" tall. A shipper wants to ship cans in a box with 2 layers. 4 rows, and 5 cans per row. The box mu
GenaCL600 [577]
Given,

Diameter of the can = 3"
Height of the can = 7"
Looking at how the cans are arranged in the box, that is 4 x 5 (4 rows of cans [width] with 5 cans in each row [length]) 

The length of the box (L) = 5 cans multiplied by each can's diameter = 5 × 3" = 15"
The width of the box (W) = 4 cans multiplied by each can's diameter) = 4 × 3" = 12"
The height of the box (H) = 2 layers of cans = 2 cans multiplied by each can's height = 2 × 7" = 14"

Therefore, the volume of the box = Length (L) × Width (W) × Height (H) = 15" × 12" × 14" = 2520 inches³

Volume of the box = 2520 inches³

=====================================================

There is also an alternative method to calculate the volume of the box:

Consider each can. Although the can is cylindrical, each can would occupy the space required by a cuboid. 

So, for each Cuboid space, the diameter of the can will be the length and width of the cuboid and the height of the can will be the height of the cuboid.

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Length (L) = 3"
Width (W) = 3"
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There are 40 such cans in total inside the box; therefore,

Volume of the box = 40 × 63 inches³ = 2520 inches³
5 0
3 years ago
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