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svlad2 [7]
3 years ago
5

What is an equation of the line that passes through the points (4, -6)and (8, -4)

Mathematics
2 answers:
kow [346]3 years ago
7 0

Answer:

y = 1/2x - 8.

Step-by-step explanation:

The slope of the line = rise / run

= (-4 - (-6)) / (8 - 4)

= 2/4

= 1/2.

Using the point/slope form of the equation of a line:

y - y1 = m(x - x1)

Here we have m = 1/2 and (x1, y1) = (4, -6):

y - (-6) = 1/2 (x - 4)

y + 6 = 1/2x - 2

y = 1/2x - 8.

QveST [7]3 years ago
3 0

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y+6=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-8

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2 years ago
Please don't answer just to say "I don't know"<br> Thank you
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3 years ago
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pav-90 [236]
The smallest region that can be photographed is
5*7 = 35 square km
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Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
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3 years ago
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3 years ago
Solve the quadratic equation.<br>m^2/15 -3 = 2​
Radda [10]

The answer is 5 \sqrt{3}

<h3>Explanation :</h3>

\frac{ {m}^{2} }{15}  - 3 = 2

\frac{ {m}^{2} }{15}  = 2  + 3

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CMIIW

7 0
2 years ago
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