Answer:
Step-by-step explanation:
8x+15 = 2x+39
8x =2x+24
6x = 24
x = 24/6 = 4
angle 4 = 2(4) +39 = 8+39 = 47
angle 6 = angle 4
angle 6 = 47 degrees
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
0.4 is 10 times as much as 0.04
this is because 0.04 times 10 is 0.4
0.003 is 1/10 of 0.03
0.003 times 10 is 0.03