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vazorg [7]
3 years ago
8

Find the difference by aligning the expressions vertically. (2x + 3y - 4) - (5x + 2)​

Mathematics
1 answer:
lys-0071 [83]3 years ago
7 0

Answer:

− 3 x + 3 y − 6

Step-by-step explanation:

If you want me to show work let me know but all you need to do is simplify the expression.

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How do I find the measurements for the missing angles?
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Answer:

I DONT KNOW IM VERY SORRY CAN JUST PLEASE GIVE ME 5 STARS I WOULD APPRECIATE IT VERY MUCH...

Step-by-step explanation:

5 0
3 years ago
Algebra 1 (pic included)
Marizza181 [45]
If you are given that b = 2, then just plug it in:
2(2)-4 = 4-4 = 0

So, your final answer is 0.
3 0
3 years ago
Mrs. Hanson has 2 pies for a party. She calculates that if she splits the pies evenly among the guests, they will each receive 1
brilliants [131]
There are 32 guests.
Proof: 1*8*2=32.
4 0
3 years ago
Read 2 more answers
How do I simply this, thanks!
stepan [7]
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3 = a^4b^9/2a^8b^4 =b^5/2a^4 so your answer is b^5/2a^4
7 0
3 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
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