Greetings from Brasil...
Let's apply the given formula:
A = (1/2)·B·H
The base of this polygon (in this case, the triangle) is B
B = X² - 2X + 6
The height of this polygon is H and is H
H = X + 4
Applying these values (B and H) in the given formula.....
A = (1/2)·B·H
A = (1/2)·(X² - 2X + 6)·(X + 4)
A = (1/2)·(X³ + 2X² - 2X + 24)
A = (X³/2) + X² - X + 12
OR
A = (X³ + 2X² - 2X + 24)/2
Answer:
like what type of help that i could help u
Answer:
answer is 88 digits
Step-by-step explanation:
Answer:
As the first part comes to the rest means, then it will fall under gravity directly.
First of all maximum height,
H=
g
u²sin²θ
H=
2×10
400×(
2
1
)
H=10m.
As initially the full projectile was supposed to land at A but due to explosion first part land at A', so to make the centre of mass lies at A the second part should lie at B.
f they don't break (explode) range OA
OA=
g
u²sin2θ
OA=400×sin45×
10
2
Answer: Y=5
Step-by-step explanation:
Your line has no slope. It is a horizontal line
