Write the inequality represented by the graph

Which shape is always a parallelogram<br> (Pentagon,trapezoid,rhombus,or triangle

Sliva [168]

A rhombus is always a parallelogram, hope that helps!

8 0

2 years ago

Kyle drew three line segments with lengths: 2/4 inch 2/3inch, and 2/6 inch list the fractions in order from least to greatest

Sati [7]

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Method 1
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Since the numerators are the same, the smaller the denominators, the greater the fraction is.

Arranging from the least to the greatest
$\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}$

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Method 2
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Lets change all to the same denominators

$\dfrac{2}{4} = \dfrac{2 \times 3}{4 \times 3} = \dfrac{6}{12}$

$\dfrac{2}{3} = \dfrac{2 \times 4}{3 \times 4} = \dfrac{8}{12}$

$\dfrac{2}{6} = \dfrac{2 \times 2}{6 \times 2} = \dfrac{4}{12}$

Now that all the denominators are the same, we can arrange the fractions by comparing the numerators. The bigger the numerators, the greater the fraction.

Arranging from the least to the greatest
$\dfrac{2}{6} \ , \ \dfrac{2}{4} \ , \ \dfrac{2}{3}$

3 0

3 years ago

Read 2 more answers

What is the equation in the slope intercept form of the line that passes through the point (2,-2) and is perpendicular to the li

Igoryamba

Answer:

D

Step-by-step explanation:

The slope is 2/5 and the slope of the new line will be -5/2 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y--2)=-5/2(x-2)

y+2=-5/2x+10/2

y=-5/2x+5-2

y= -5/2x+3

5 0

3 years ago

Read 2 more answers

If the maximum acceleration that is tolerable for passengers in a subway train is 1.74 m/s2 and subway stations are located 930

Free_Kalibri [48]

Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.

Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by
$s=ut+ \frac{1}{2} at^2$

But, we assume that the train accelerates from rest, thus
$s=\frac{1}{2} at^2 \\ \\ \Rightarrow465=\frac{1}{2}(1.74)t^2 \\ \\ \Rightarrow t^2=534.48 \\ \\ \Rightarrow t=\sqrt{534.48}=23.12$

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).

Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.

6 0

3 years ago

Please solve!! solve for y 3x-y=16<br><br> Will name the Brainliest!!

algol [13]

Answer:

y= 5.333

Step-by-step explanation:

4 0

2 years ago