Answer:
112.569 ( D )
Step-by-step explanation:
Applying the estimated Regression Equation
y = b1X1 + b2X2 + a
b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884
b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925
a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252
y = 0.939X1 + 0.309X2 + 31.733
For x1 ( age ) =39, and x2(weight) =143
y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569
where
Sum of X1 = 981
Sum of X2 = 3102
Sum of Y = 2388
Mean X1 = 61.3125
Mean X2 = 193.875
Mean Y = 149.25
attached is the Tabular calculation of the required values needed for estimated regression equation
<u>Answer:</u>
The amount lost over the 3 years s 2567.25£
<u>Explanation:</u>
where F = final value after n years
I = initial value of the car in 2017 = £18000 (given)
Since the value is depreciated 5% every year for 3 years,
r = percentage rate of depreciation = 5% (given)
n = 3 years
Substituting these values in formula, we get
=
= 15432.75£ which is the value of the car after 3 years
Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.
Answer:
$48.5
Step-by-step explanation:
Given data
Number of purses= 14+2= 16
Cost of 14 purses= $50
Cost of 2 purses= $38
Let us use the weighted cost method
Mean cost = (14*50+ 2*38)/16
Mean cost = (700+ 76)/16
Mean cost = 776/16
Mean cost =$48.5
Answer:
Step-by-step explanation:
A = 1/4 pie d2
= 1/4(22/7)(12)2
= 1/4(22/7)144
= 113.1