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4 years ago

Find the elapsed time

Mathematics

1 answer:

liq [111]4 years ago

6 0

Step-by-step explanation:

4:15 p.m. to 5.00 p.m. → 45min

5:00 p.m. to 10:00 p.m. → 5h

Answer: 5h 45min

3:45 a.m. to 4.00 a.m. → 15min

4.00 a.m. to 12:00 p.m. → 8h

Answer: 8h 15min

1:15 p.m. to 2:00 p.m. → 45min

2:00 p.m. 8:00 p.m. → 6h

8:00 p.m. to 8:11 p.m. → 11min

Answer: 6h (45 + 11)min = 6h 56min

2:37 a.m. to 3:00 a.m. → 23min

3:00 a.m. to 3:15 a.m. → 15min

Answer: (23 + 15)min = 38min

11:59 a.m. to 12:00 p.m. → 1min

12:00 p.m. to 1:00 p.m. → 1h

1:00 p.m. to 1:01 p.m. → 1min

Answer: 1h (1 + 1)min = 1h 2min

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Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

3 years ago

Two more than 16 times a number is the same as 21 less than the product of -7 and the number

erastova [34]

16x+2=-7x-21

x = -1

So yeah

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4 years ago

The ratio of two complementary angles is 7:2. What is the measure, in degrees, of the larger angle?

lisabon 2012 [21]

Answer:

70 degrees

Step-by-step explanation:

Complementary angles sum up to 90.

To find the larger angle, you find the total of the values in the ratio, divide the larger value of the ratio by the total and multiply it by 90.

(7/7+2)×90=7/9×90

=7×10

=70

Write an equation:

7x+2x=90

9x=90

x=10

Then multiply x by the larger value.

7x=7 (10)=70

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Alenkinab [10]

Please include the relation(s).

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4 years ago

The localist meteorologist is converting temperatures from Celsius to Fahrenheit. She knows that the formula for the conversion

bazaltina [42]

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---- = F - 32. Now add 32 to both sides:

9C 9C + 160

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3 years ago