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Naddik [55]
3 years ago
7

Find the elapsed time

Mathematics
1 answer:
liq [111]3 years ago
6 0

Step-by-step explanation:

1.

4:15 p.m. to 5.00 p.m. → 45min

5:00 p.m. to 10:00 p.m. → 5h

Answer: 5h 45min

2.

3:45 a.m. to 4.00 a.m. → 15min

4.00 a.m. to 12:00 p.m. → 8h

Answer: 8h 15min

3.

1:15 p.m. to 2:00 p.m. → 45min

2:00 p.m. 8:00 p.m. → 6h

8:00 p.m. to 8:11 p.m. → 11min

Answer: 6h (45 + 11)min = 6h 56min

4.

2:37 a.m. to 3:00 a.m. → 23min

3:00 a.m. to 3:15 a.m. → 15min

Answer: (23 + 15)min = 38min

5.

11:59 a.m. to 12:00 p.m. → 1min

12:00 p.m. to 1:00 p.m. → 1h

1:00 p.m. to 1:01 p.m. → 1min

Answer: 1h (1 + 1)min = 1h 2min

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State the domain of the relation {(0, 5), (5, 2), (0, −4), (1, 5)}.
disa [49]

Answer: B

Step-by-step explanation:

State the domain of the relation {(0, 5), (5, 2), (0, −4), (1, 5)}.

8 0
2 years ago
573÷3 i feel like i did something wrong with the 27
Tom [10]
You did everything right. The correct answer is 191

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4 0
2 years ago
Which proportion can you use to find the value of a?
Ugo [173]

<u>Given</u>:

The given triangle is a similar triangle.

The length of the hypotenuse is 18 units.

The length of the leg is a.

The length of the part of the hypotenuse is 16 units.

We need to determine the proportion used to find the value of a.

<u>Proportion to find the value of a:</u>

We shall find the proportion to determine the value of a using the geometric mean leg rule.

Applying the leg rule, we have;

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

Substituting the values of hypotenuse, leg and part, we get;

\frac{18}{a}=\frac{a}{16}

Thus, the proportion used to find the value of a is \frac{18}{a}=\frac{a}{16}

Hence, Option D is the correct answer.

6 0
3 years ago
The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran
VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, X = "Comprehensive strength of concrete". We have information that X is normally distributed with a mean of 2500 psi and a standard deviation of  50 psi (or a variance of 2500 psi). In other words, X \sim N(2500, 2500).

We want to know the probability of the mean of X or \bar{X} that falls in the interval [2499;2510]. From inference theory we know that :

\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)

Now we can find the probability as follows:

P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )

Where Z \sim N(0,1), then:

P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798

8 0
3 years ago
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