Yup! Consider the circle:
r=cnt, for any angle. Impossible with (x,y), because for a given x, you need to y values. For a circle of radius 1, centered at the origin, y = +sqrt( 1-x^2) and y = -sqrt(1-x^2)
Also the spiral, etc ... Any hta has for one x value, two or more y values.
Answer: Fourth option
Please, see the attached file.
Thanks.
Answer:
30
Step-by-step explanation:
2x^3+3y-4
2(2)^3+3(6)-4
2(8)+18-4
16+18-4
30