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weqwewe [10]
3 years ago
12

In a group of kangaroos, the two lightest kangaroos weigh 25% of the total weight of the group. The three heaviest kangaroos wei

gh 60% of the total weight. How many kangaroos are in the group?
Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

6 kangaroos

Step-by-step explanation:

25% + 60% = 85%

15% can be only one because the two lightest are 25% of the total.

2+1+3 = 6

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Please help<br>much appreciated ​
S_A_V [24]

Answer:

P = 2x + 2y + 8

Step-by-step explanation:

The perimeter (P) of a rectangle is calculated as

P = 2(l + w) ← l is length and w is width , then

P = 2(x + 5 + y - 1) ← distribute parenthesis

  = 2x + 10 + 2y - 2 ← collect like terms

  = 2x + 2y + 8

6 0
3 years ago
1. 5 + n2 &gt; 8 2. -4 - 5v 12
pogonyaev
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8 0
3 years ago
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There is 1/4 ounce of yeast in every 2 1/4 teaspoon of yeast. A recipe calls for 2 teaspoons of yeast. How many ounces of yeast
MrRissso [65]
1/4 ounce of yeast ... 2 1/4 teaspoons of yeast
x ounce of yeast = ? ... 2 teaspoons of yeast

If you would like to know how many ounces of yeast need to be in the recipe, you can calculate this using the following steps:

1/4 * 2 = x * 2 1/4
1/2 = x * 9/4     /*4/9
x = 1/2 * 4/9
x = 2/9

Result: 2/9 ounce of yeast needs to be in this recipe.
7 0
3 years ago
Hank has to drain his pool so repairs can be done on a crack on the bottom. The company coming to fix the pool is scheduled to a
Alik [6]

Answer:

The answer to the question: "Will Hank have the pool drained in time?" is:

  • <u>Yes, Hank will have the pool drained in time</u>.

Step-by-step explanation:

To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:

  • Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
  • Available time =  360 minutes

Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:

  • Volume of the pool = Deep * Long * Wide
  • Volume of the pool = 2 m * 10 m * 8 m
  • Volume of the pool = 160 m^3

Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:

  • 1 m^3 = 264.172 gal

Now, we use a rule of three:

If:

  • 1 m^3 ⇒ 264.172 gal
  • 160 m^3 ⇒ x

And we calculate:

  • x = \frac{160 m^{3}*264.172 gal }{1m^{3} } (We cancel the unit "m^3)
  • x = 42267.52 gal

At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:

  • Time to drain the pool =\frac{42267.52gal}{130\frac{gal}{min} }(We cancel the unit "gallon")
  • Time to drain the pool = 325.1347692 minutes
  • <u>Time to drain the pool ≅ 326 minutes</u> (I approximate to the next number because I want to assure the pool is drained in that time)

As we know, <u><em>Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes</em></u>.

7 0
3 years ago
Need help asap pllzzz will give brainliest
Greeley [361]

Answer:

d. $350.00

Step-by-step explanation:

A constant is a number that does not have any variables. The additional cost would depend on the number of persons at attendance so the cost would be $10.00p which is not the constant here. Thus, $350.00 is the only constant in this situation.

4 0
3 years ago
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