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ludmilkaskok [199]
3 years ago
5

TIMED FINAL. WILL GIVE BRAINLIEST IF ANSWERED IN THE NEXT HOUR. I NEED THE ANSWER ASAP.

Mathematics
2 answers:
Verizon [17]3 years ago
6 0

Answer:

D

Step-by-step explanation:

larisa86 [58]3 years ago
5 0

Answer:

I I'm not 100percent sure but i believe the answere should be D.The cauliflower function has a greater slope, which shows that the cost per pound of cauliflower is greater than the cost per pound of broccoli.

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Evaluate.<br> 13[42–(2+4)]
german

Answer:

468

Step-by-step explanation:

=13[42-6]

=13 (36)

=13×36

=468

6 0
3 years ago
4x what is close to 97
Hitman42 [59]

Lets try  96

4 x  ?= 96

? = 96/4

= 24

So we see that 4 times 24 is close to 97.

7 0
3 years ago
Need help for question 3! 98 points and brainliest!
Softa [21]

1: $68

2: 45(5)=225

-TTL

6 0
3 years ago
Read 2 more answers
What is the value of the expression below? 2[3(42+1)]-23
s2008m [1.1K]

Answer:

235

Step-by-step explanation:

42+1

43

3 times 43

129

129 times 2

258

258-23

235

4 0
3 years ago
Read 2 more answers
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
3 years ago
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